Step of Proof: mul_cancel_in_eq
12,41
postcript
pdf
Inference at
*
1
I
of proof for Lemma
mul
cancel
in
eq
:
1.
a
:
2.
b
:
3.
n
:
((
n
*
a
) = (
n
*
b
))
(
a
=
b
)
latex
by ((Assert
m
:
. ((
m
*
a
) = (
m
*
b
))
(
a
=
b
))
CollapseTHEN ((Auto_aux (first_nat 1:n
C
) ((first_nat 1:n),(first_nat 3:n)) (first_tok :t) inil_term)))
latex
C
1
:
C1:
4.
m
:
C1:
5. (
m
*
a
) = (
m
*
b
)
C1:
a
=
b
C
2
:
C2:
4.
m
:
. ((
m
*
a
) = (
m
*
b
))
(
a
=
b
)
C2:
5. (
n
*
a
) = (
n
*
b
)
C2:
a
=
b
C
.
Definitions
,
t
T
,
x
:
A
.
B
(
x
)
,
P
Q
,
,
Lemmas
nat
plus
wf
origin